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- Solved O O w 3 E 3 O OOK Ń A 0 0 4 + л 0 O un ď A л mo - Chegg
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- Solved Air at p = 1 atm enters a thin-walled (D = 5-mm - Chegg
Engineering Mechanical Engineering Mechanical Engineering questions and answers Air at p = 1 atm enters a thin-walled (D = 5-mm diameter) long tube (L = 2 m) at an inlet temperature of Tm,i = 100°C A constant heat flux is applied to the air from the tube surface The air mass flow rate is ń = 135 x 10-6 kg s If the tube surface temperature at the exit is Tso = 160°C, determine the heat
- Solved Problem 9. 1. 6 A 0. 10-m-diameter circular cylinder - Chegg
Engineering Mechanical Engineering Mechanical Engineering questions and answers Problem 9 1 6 A 0 10-m-diameter circular cylinder moves through air with a speed U The pressure distribution on the cylinder's surface is approximated by the three straight-line segments shown in Fig P9 1 6 Determine the drag coefficient on the cylinder Neglect shear forces 3 2 1 0 p (N m²) -1 or or b w Ń -3
- Solved A given steady flow of a perfect gas in a | Chegg. com
A given steady flow of a perfect gas in a constant-area duct is affected by friction For subsonic flows the wall friction coefficient is not very sensitive to Mach number and may be represented approximately (for smooth-walled ducts) as ń -0 2 C = 0 045 25 ( VAMI the same as for incompressible flow Consider two ducts operating with an inlet Mach number of 0 2 and y = 1 4 With a Reynolds
- Solved 4. A closed-form expression for the mass flowrate, m . . . - Chegg
A closed-form expression for the mass flowrate, m, through a choked nozzle is (7+1) (-1) PA ń VTVR 7+1 where, Po and To are total pressure and total temperature, respectively; A, is the throat area; 7 is the gas specific heat; R is the gas constant Derive this expression ( () Show transcribed image text Here’s the best way to solve it
- Solved -16 -7 20 15 4 -1 2 -2 7 10 [A] = -5 -12 -13 -14 -6 - Chegg
Question: -16 -7 20 15 4 -1 2 -2 7 10 [A] = -5 -12 -13 -14 -6 18 12 16 -8 - 15 If matrix [A] has element arc = 12, what is r and c? T = and c = -9 7 9 9 6 Ń w بس یہ 0 -7 -6 -2 -9 [E] -4 -3 [A] 4 6 8 4 -5 7 2 -6 -5 -10 8 0 5 [E] - [A] = JI10 Suppose the matrix C is transformed into the identity by two elementary matrices, as shown below: C= What is C? 3 What is
- Solved 8. 2 The Lipid Bilayer 47. Classify the following - Chegg
8 2 The Lipid Bilayer 47 Classify the following molecules as polar, nonpolar, or amphipathic: a CH3CH2CH=CHCH)3 (CH2)6C00 b CH2-OH HC-OH CH2-OH c CH2-0-C- (CH),CH=CH (CH),CH, o- HO-C-H CH2-OH d (CH216 CH3 e CH2–0-C- (CH2) 140Hz C-0-0-H O (CH2), CH2-0-1-0- (CH2)2-Ń (CH3)3 25-0---0- CH || CH (CH2)7 CH3 48 Which molecules in Problem 47 can form bilayers? For the mole- cules that do not
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