- If 8, 2 are roots of the equation x^2 + ax + beta and 3, 3 are roots o
Step by step video image solution for If 8, 2 are roots of the equation x^2 + ax + beta and 3, 3 are roots of x^2 + alpha x + b = 0 then roots of the equation x^2+ax+b =0 are by Maths experts to help you in doubts scoring excellent marks in Class 11 exams
- If 8 and 2 are the roots of x2+ax+β=0 and 3, 3 are the roots of x2+αx+b . . .
The correct answer is If 8, 2 are roots of x2+ax+β=0 then8+2=−a⇒ a=−103, 3 are roots of x2+αx+b=0 then3 (3)=b⇒ b=9∴ The Equation x2+ax+b=0⇒ x2−10x+9=0⇒ (x−1) (x−9)=0⇒ x= 1, 9
- If \\ [\\ { 8,2\\} \\] are the roots of \\ [ {x^2} + ax + \\beta = 0 . . .
It is given that, {8, 2} are the roots of x 2 + a x + β = 0 Also, given that, {3, 3} are the roots of x 2 + α x + b = 0 We have to find the roots of the equation x 2 + a x + b = 0 Before finding the roots of the given equation, at first, we will find the value of a, b Let us consider, p, q be the roots of a quadratic equation
- If 8 and 2 are the roots of x^2 + ax + c = 0 and 3, 3 are the roots of . . .
If 8 and 2 are the roots of x2 + ax + c = 0 and 3, 3 are the roots of x2 + ax + b = 0, then the roots of the equation x2 + ax + b = 0 are … (a) 1, 2 (b) -1, 1 (c) 9, 1 (d) -1, 2
- If 8,2 are the roots of x^2 + ax + beta = 0 and 3,3 are the roots of x . . .
If 8,2 are the roots of x^2 + ax + beta = 0 and 3,3 are the roots of x^2 + ax + b = 0 then find the roots of x^2 + ax + b = 0 EXPLANATION 8, 2 are the roots of quadratic equation x² + ax + β = 0 3, 3 are the roots of quadratic equation x² + αx + b = 0 As we know that, α and β are the zeroes of the quadratic polynomial
- Choose the correct alternative:If 8 and 2 are the roots of x2 + ax + c . . .
Quadratic Functions Is there an error in this question or solution?
- If 8,2 are the roots of x^ (2)+ax+beta=0 and 3,3 are the roots of x^ (2)
To solve the problem, we need to find the roots of the quadratic equation x2+ax+b= 0 given that the roots of two other quadratic equations are provided The roots of the first equation x2+ax+β =0 are given as 8 and 2 - The sum of roots is given by −a (where a is the coefficient of x) - The product of roots is given by β (the constant term)
- If 8, 2 are the roots of x2+ax+β=0 and 3, 3 are the roots of x2+αx+b=0 . . .
The correct answer is 8, 2 are the roots of x2+αx+β=0∴8+2=10=-a, 8 2=16=β i e α=-10, β=163, 3 are the roots of x2+αx+b=0∴3+3=6=-α, 3 3=b i e α=-6, b=9Now, x2+ax+b=0 becomes x2-10+9=0or (x-1) (x-9)=0⇒x=1, 9
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