Why is the chemical formula for vinegar CH3COOH what it is? CH3COOH is an accepted and common form of writing the structure of acetic acid (commonly known as vinegar when diluted in water) You are right in saying the formal notation should be used - which is C2H4O2 - since it gives the reader the types of atoms and their quantities, and these two characteristics define the exact composition of the
physical chemistry - Which way does this reaction between NaCl and . . . (sodium acetate + hydrochloric acid ↽−−⇀ ↽ ⇀ sodium chloride + acetic acid) Which way does the above reaction naturally proceed? I've tried Googling this, but different sources seem to suggest contradictory answers, and I can't really tell what's correct
physical chemistry - How is the dissolution of acetic acid that makes . . . So before dissolution, we are dealing with molecules of acetic acid If we add these into water, most of them just stay being molecules; only a small percentage ionises in water according to reaction (2) (2) The acidity constant shown in the equation is a measure of how many molecules are dissociated; it depends on the concentration