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- What are the spectator ions in the reaction between sodium . . . - Socratic
The nitrate and the natrium ions Na_2CO_3(aq) + 2AgNO_3(aq) rarr Ag_2CO_3(s)darr + 2NaNO_3(aq) The net ionic equation is: 2Ag^(+) + CO_3^(2-) rarr Ag_2CO_3(s)darr
- What is the chemical formula for lithium hydroxide? - Socratic
Lithium is a Group 1 metal and commonly forms a M + ion Hydroxide anion, −OH, has a unit negative charge When they make music together, there is thus 1:1 stoichiometry between ions: Li(s) + H 2O(l) → LiOH (aq) + 1 2 H 2(g) ↑ ⏐ ⏐⏐
- What is the formula of magnesium hydroxide? | Socratic
Mg (OH)_2 Now we know that hydroxides are salts of HO^-, and some metal ion Now if the parent metal has an electronic configuration of 2:8:2, then there are 12 electrons, and the atomic number of the metal is equal to 12 We look on the Periodic Table, and we find that Z=12, for "magnesium metal" As a Group 2 metal, magnesium forms a Mg^ (2+) ion, and hence its hydroxide is Mg (OH)_2
- 0. 10 moles of sodium cyanate dissolved in 250cm^3 distilled . . . - Socratic
The cyanate anions will react with water to form isocyanic acid, HNCO, and hydroxide anions, OH− This tells you that you can expect the pH of the resulting solution to be higher than 7 Calculate the molarity of the sodium cyanate solution by using the given number of moles and volume Keep in mind that you need to use liters of solution and
- Could a buffered solution be made by mixing aqueous . . . - Socratic
Could a buffered solution be made by mixing aqueous solutions of HCl and NaOH? Explain Why isn't a mixture of a strong acid and its conjugate base considered a buffered solution?
- What makes for a good leaving group? + Example - Socratic
A good leaving group has to be able to part with its electrons easily enough, so typically, it must be a strong acid or weak base relative to other substituents on the same molecule It helps to know the pKa of what would be leaving Let's say you had a mechanism where you are trying to do an E2 reaction to make an -OH (hydroxyl) group leave Maybe you have this compound on hand, sec-butanol
- Question #22e51 - Socratic
See the answer below; Having; Cu (OH)_2 + HCl -> ? Products formed are; Cu (OH)_2 + HCl -> CuCl_2 + H_2O Since CuCl_2 is soluble in water But; Cu (OH)_2 + HCl
- Question #ccabf - Socratic
Because N aOH → N a+ + OH − and N i2+ + 2OH −→N i(OH)2 Total Mols of N aOH: 60mL ⋅ 0 45M ol L = 27mM ol of N aOH (dont forget the m for milli=one thousandth) This will produce 27 2 = 13 5mM ol of N i(OH)2 Now you multiply this by the molecular mass number to get the weight in milligrams (divide by 1000 to get the grams) Nickel (II)hydroxide may be formed without or (more likely
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