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  • 5%氯化钠溶液怎么配置 - 百度经验
    我们先列出如下所示的方程式，在公式中假设"x“为配制5%氯化钠溶液所需的氯化钠固体的质量，经计算可得"x"的值为12 5g。此时我们利用分析天平称取12 5g的氯化钠后先其溶解，然后将溶解的溶液加到容量瓶中，最后定容到250ml即可。




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