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  • html - What do lt; and gt; stand for? - Stack Overflow
    I know that the entities lt; and gt; are used for < and >, but I am curious what these names stand for Does lt; stand for something like "Left tag" or is it just a code?
  • Which characters need to be escaped in HTML? - Stack Overflow
    527 Short answer If you're putting the text in a safe location in a document that uses a fully-Unicode-compatible text encoding like UTF-8, HTML only requires the same five characters to be escaped as XML: the ampersand as amp;, the less-than sign < as lt;, the greater-than sign > as gt;, the double-quote " as ", and the single-quote ' as
  • javascript - Difference between lt and lt; - Stack Overflow
    Difference between " lt" and "<" Asked 11 years, 7 months ago Modified 11 years, 7 months ago Viewed 3k times
  • Para que sirve el gt y el lt en un native query?
    El artículo explica el uso de los caracteres gt; y lt; en consultas nativas SQL
  • Replace all strings lt; and gt; in a variable with lt; and gt;
    In order to make the HTML code XML-readable, I have to replace the code brackets with the corresponding symbol codes, i e < with lt; and > with gt; The formatted text gets transferred as HTML code with the variable inputtext, so we have for example the text The <b>Genji< b> and the <b>Heike< b> waged a long and bloody war
  • java - why is lt; showing as lt; - Stack Overflow
    4 lt; is the way to show "<" in html, which is produced from XMLHttpRequest try using XMLRequest answered Jun 11, 2009 at 15:39
  • convert lt to lt; xml document - Stack Overflow
    Something like *-lt-* will probably do Have the parser produce the file save it Read in the file as plaintext, and replace your instances of *-lt-* with the regular < character Re-write the file, clobbering the version that was written by the XML parser
  • bash - Shell equality operators (=, ==, -eq) - Stack Overflow
    It depends on the Test Construct around the operator Your options are double parentheses, double brackets, single brackets, or test If you use ((…)), you are testing arithmetic equality with == as in C: $ (( 1==1 )); echo $? 0 $ (( 1==2 )); echo $? 1 (Note: 0 means true in the Unix sense and a failed test results in a non-zero number ) Using -eq inside of double parentheses is a syntax




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