|
- Finding the limit when denominator = 0 - Mathematics Stack Exchange
I'm having trouble solving this limit: $$\\lim_{x \\to -2^-} \\frac{1}{(x + 2)^2}$$ I can't find a way to rationalize the denominator Also, is there a way to do it without plugging in -2 001 and st
- I have learned that 1 0 is infinity, why isnt it minus infinity?
@Swivel But 0 does equal -0 Even under IEEE-754 The only reason IEEE-754 makes a distinction between +0 and -0 at all is because of underflow, and for + - ∞, overflow The intention is if you have a number whose magnitude is so small it underflows the exponent, you have no choice but to call the magnitude zero, but you can still salvage the
- Mathematics Stack Exchange
Q A for people studying math at any level and professionals in related fields
- Is $0$ a natural number? - Mathematics Stack Exchange
Inclusion of $0$ in the natural numbers is a definition for them that first occurred in the 19th century The Peano Axioms for natural numbers take $0$ to be one though, so if you are working with these axioms (and a lot of natural number theory does) then you take $0$ to be a natural number
- linear algebra - How to tell if a set of vectors spans a space . . .
Generically you don't know without examing the presumed "basis" vectors You do know that three vectors are sufficient (x,y,z) to span 3-space; any fourth vector must be a linear combination of (x,y,z) There is no more room
- How do I explain 2 to the power of zero equals 1 to a child
My daughter is stuck on the concept that $$2^0 = 1,$$ having the intuitive expectation that it be equal to zero I have tried explaining it, but I guess not well enough How would you explain the
- Proof of $0x=0$ - Mathematics Stack Exchange
Since $0$ is the neutral element for the addition, we have that $$0x = (0 + 0)x$$ and because of distributivity we find that $$ (0 + 0)x = 0x + 0x $$ Hence we find that $$0x = 0x + 0x$$ so $0x$ also acts as the neutral element Because of unicity of this element, we have that $0x = 0$ $\textbf {Edit:}$ As Will Jagy commented, you could also use that $0x$ has an additive inverse, denoted by
- Show that ∇· (∇ x F) = 0 for any vector field [duplicate]
Show that ∇· (∇ x F) = 0 for any vector field [duplicate] Ask Question Asked 9 years, 7 months ago Modified 9 years, 7 months ago
|
|
|