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  • Question #b5f73 - Socratic
    Then, we can just find the mass of 2 272 carbon atoms by multiplying 2 272 by the mass of 1 mole of carbon: 2 272 xx 12 01 = "27 29g" Since there was 1 significant figure in the question, our answer is "30g" Another way to solve this problem is by using the mass percent!
  • Question #b5e69 - Socratic
    Explanation: #M_ (CO_2) = "220 mg"# #MW_ (CO_2) = "44 01 g mol"# #"O"_2 " molecules = ?"#
  • Question #bae89 - Socratic
    Comparing the intensity levels of two different sounds of intensities I_1 and I_2, IL_2 - IL_1 = (10 dB) [\log_ {10} (I_2 I_0) - \log_ {10} (I_1 I_0)] But, \qquad \log_ {10} (a) - \log_ {10} (b) = \log_ {10} (a b) IL_2 - IL_1 = (10 dB)\log_ {10} (I_2 I_1) IL_1 = IL_2 - (10 dB)\log_ {10} (I_2 I_1) The intensity of sound wave produced by two
  • Question #004f2 - Socratic
    0 56 1 molar solution ="Number of moles of solute" "Volume of solution" for Sugar C_ (12)H_ (22)O_ (11) molar mass=342gm according to equation and information provided 1= (3 42 342) x where x is the volume of solution in l : the volume of solution is 0 01 l which is 10 ml : 10 gm of water moles of solute=3 42 342=0 01 moles of solution =10 18=0 55 : the mole fraction of the solution is 0
  • If #a^2 + b^2 = c^2# = 12. 85 and ab=5. 58, then (a + b)^2 - Socratic
    (a+b)^2=24 01 >"note that " (a+b)^2=a^2+2ab+b^2 color (white) (xxxxx)=a^2+b^2+2ab color (white) (xxxxx)=12 85+ (2xx5 58) color (white) (xxxxx)=12 85+11 16=24 01
  • 1545 subjects were given ginko 1524 placebo. In ginko . . . - Socratic
    1545 subjects were given ginko 1524 placebo In ginko group, 246 developed dementian in the placebo it was 277 with dementia Significance level=0 01 to test claim (ginko is effective in dementia) Can you test claim and construct confidence interval? Statistics
  • How do you use the important points to sketch the graph of # . . . - Socratic
    Now, calculate the intercepts with the y-axis #x=0#, #=>#, #y=2# So a point is # (0,2)# Now, calculate the intercepts with the x-axis #y=0#, #=>#, #2x^2+2=0# #=>#, #x^2+1=0# #x^2=-1# There are no intercepts with the x-axis When #x=-x#, the curve does not change The axis of symmetry is #x=0# And the minimum point is # (0,2)# Now, you can sketch the curve graph {2x^2+2 [-16 02, 16 01, -8 01, 8
  • Question #cbccf - Socratic
    The concentration of "Pb"^"2+" at equilibrium is 9 3 × 10^"-5"color (white) (l) "mol L" > We can solve this by setting up an ICE table color (white) (mmmmmm)"Pb (s




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