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- Question #b5f73 - Socratic
Then, we can just find the mass of 2 272 carbon atoms by multiplying 2 272 by the mass of 1 mole of carbon: 2 272 xx 12 01 = "27 29g" Since there was 1 significant figure in the question, our answer is "30g" Another way to solve this problem is by using the mass percent!
- 1545 subjects were given ginko 1524 placebo. In ginko . . . - Socratic
1545 subjects were given ginko 1524 placebo In ginko group, 246 developed dementian in the placebo it was 277 with dementia Significance level=0 01 to test claim (ginko is effective in dementia) Can you test claim and construct confidence interval? Statistics
- Question #bae89 - Socratic
Comparing the intensity levels of two different sounds of intensities I_1 and I_2, IL_2 - IL_1 = (10 dB) [\log_ {10} (I_2 I_0) - \log_ {10} (I_1 I_0)] But, \qquad \log_ {10} (a) - \log_ {10} (b) = \log_ {10} (a b) IL_2 - IL_1 = (10 dB)\log_ {10} (I_2 I_1) IL_1 = IL_2 - (10 dB)\log_ {10} (I_2 I_1) The intensity of sound wave produced by two
- Question #004f2 - Socratic
0 56 1 molar solution ="Number of moles of solute" "Volume of solution" for Sugar C_ (12)H_ (22)O_ (11) molar mass=342gm according to equation and information provided 1= (3 42 342) x where x is the volume of solution in l : the volume of solution is 0 01 l which is 10 ml : 10 gm of water moles of solute=3 42 342=0 01 moles of solution =10 18=0 55 : the mole fraction of the solution is 0
- Question #fe281 - Socratic
4 ⋅ 12 01 = 48 04 g We now know that one mole of carbon contains 48 04 grams of carbon Next, we determine how many grams of carbon are in one mole of CO 1 ⋅ 12 01 = 12 01 g Now, we know that one mole of CO contains 12 01 grams of carbon With this information, we can determine how many moles of CO can be formed with the given mass of C
- Question #7908b - Socratic
65 0 "g N"_2 Any time you want to convert between moles and grams of a substance, you must know that substance's molar mass, which is the mass of one mole of that substance (One mole is equal to Avogadro's number (6 022xx10^23) of individual particles molecules of that substance ) To find the molar mass of a nitrogen molecule, we'll first realize its chemical formula, which is "N"_2 Most
- Question #18488 - Socratic
The degree of dissociation sf (alpha=0 0158) sf (K_b=2 51xx10^ (-6)color (white) (x)"mol l") Triethyamine is a weak base and ionises: sf ( (CH_3)_3N+H
- How many molecules of N_2O_3 are present in 28. 3 g of N_2O_3? - Socratic
2 228 × 10^"23" molecules 1 mole contains 6 022140857 × 10^"23" (Avogadro's number) The molecular weight of N_2O_3 is: 76 01 g mol You have 28 3 g, so you have 28 3 76 01 = 0 37 mole Hence you have 0 37 × 6 022140857 × 10^"23" = 2 228 × 10^"23" You have 2 228 × 10^"23" molecules
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