- How much zeros has the number $1000!$ at the end?
1 If a number ends with n n zeros than it is divisible by 10n 10 n, that is 2n5n 2 n 5 n A factorial clearly has more 2 2 s than 5 5 s in its factorization so you only need to count how many 5 5 s are there in the factorization of 1000! 1000!
- What does it mean when something says (in thousands)
It means "26 million thousands" Essentially just take all those values and multiply them by 1000 1000 So roughly $26 $ 26 billion in sales
- algebra precalculus - Partitions using only powers of two on $1000 . . .
How many ways are there to write $1000$ as a sum of powers of $2,$ ($2^0$ counts), where each power of two can be used a maximum of $3$ times Furthermore, $1+2+4+4$ is the same as $4+2+4+1$
- Bayes theorem tricky example - Mathematics Stack Exchange
In a certain population, 1% of people have a particular rare disease A diagnostic test for this disease is known to be 95% accurate when a person has the disease and 90% accurate when a person doe
- Look at the following infinite sequence: 1, 10, 100, 1000, 10000,
What is the proof that there are 2 numbers in this sequence that differ by a multiple of 12345678987654321?
- probability of an event occuring with numerous attempts
Often in calculating probabilities, it is sometimes easier to calculate the probability of the 'opposite', the technical term being the complement Because if something happens with probability p p, then it does not happen with probability 1 − p 1 p, e g if something happens with probability 0 40 0 40 (40% 40 %) then it does not happen with probability 1 − 0 40 = 0 60 1 0 40 = 0 60 (60%
- combinatorics - Find the number of times $5$ will be written while . . .
Question: Find the number of times 5 5 will be written while listing integers from 1 1 to 1000 1000 Now, it can be solved in this fashion The numbers will be of the form: 5xy, x5y, xy5 5 x y, x 5 y, x y 5 where x, y x, y denote the two other digits such that 0 ≤ x, y ≤ 9 0 ≤ x, y ≤ 9 So, x, y x, y can take 10 10 choice each
- What is the number of triples (a, b, c) of positive integers such that . . .
Your computation of N = 10 N = 10 is correct and 100 100 is the number of ordered triples that have product 1000 1000 You have failed to account for the condition that a ≤ b ≤ c a ≤ b ≤ c
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