- probability - 1 1000 chance of a reaction. If you do the action 1000 . . .
A hypothetical example: You have a 1 1000 chance of being hit by a bus when crossing the street However, if you perform the action of crossing the street 1000 times, then your chance of being
- If you toss $1000$ fair coins $10$ times each, what is the probability . . .
Essentially, $1000 1024$ is the average number (or "expected" number) of coins that will have come up all heads, but that includes the cases where more than one coin comes up heads all the time, so it doesn't work as a probability Consider the case where you flip two coins once each What is the odds that one coin ended up heads?
- algebra precalculus - Which is greater: $1000^ {1000}$ or $1001^ {999 . . .
The way you're getting your bounds isn't a useful way to do things You've picked the two very smallest terms of the expression to add together; on the other end of the binomial expansion, you have terms like $999^ {1000}$, which swamp your bound by about 3000 orders of magnitude
- Creating arithmetic expression equal to 1000 using exactly eight 8s . . .
I would like to find all the expressions that can be created using nothing but arithmetic operators, exactly eight $8$'s, and parentheses Here are the seven solutions I've found (on the Internet)
- What does X% faster mean? - Mathematics Stack Exchange
29 I was reading something today that was talking in terms of 10%, 100% and 1000% faster I assumed that 10% faster means it takes 10% less time (60 seconds down to 54 seconds) If that is correct wouldn't 100% faster mean 0 time and 1000% mean traveling back in time?
- terminology - What do you call numbers such as $100, 200, 500, 1000 . . .
What do you call numbers such as $100, 200, 500, 1000, 10000, 50000$ as opposed to $370, 14, 4500, 59000$ Ask Question Asked 13 years, 11 months ago Modified 9 years, 6 months ago
- Show that $|f(p_n)| lt;10^{-3}$ whenever $n gt;1$ but that $|p-p_n| lt;10^{-3 . . .
well, do you know how to compare $n^ {-10}$ and $ (n+1)^ {-10}$? can you see how small $2^ {-10}$ is compared to $10^ {-3}$?
- Finding the remainder of $N= 10^ {10}+10^ {100}+10^ {1000}+\cdots+10 . . .
$3^ {10}+3^ {100}+3^ {1000}+\dots \equiv 3\cdot 3^ {9}+3\cdot 3^ {99}+3\cdot 3^ {999}+\dots$ $\equiv 3\cdot (-1)+3\cdot (-1)+3\cdot (-1)+\dots\pmod {7}$ Again using the fact that we can replace multiplicands with something they are equivalent to Now, we make normal arithmetic simplifications:
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