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- Properties of The Number 137 - Mathematics Stack Exchange
There are some other Properties for $137$ in Wikipedia I found another Properties such that $137=2^7+2^3+1$ or the only way to write the number $137$ as a summation of two square numbers is $137=4^2+11^2$ thanks for your advice and suggestions Edit: After reading comments and answers, I want to suggest a definition for such numbers like $137$
- Find an integer $r$ with $0 ≤ r ≤ 10$ such that $7^ {137 }≡ r (\text . . .
Your working is fine You need to end by noting that $-5 \equiv 6 \pmod {11}$ since they asked for a residue between $0$ and $10$ An alternative approach would be: $7^ {137} \equiv (-4)^ {137} \equiv -2^ {274} \equiv - (2^ {5})^ {54} \cdot 2^4 \equiv - (32)^ {54} \cdot 16 \equiv - (-1)^ {54} \cdot 16 \equiv - 16 \equiv -5 \equiv 6 \pmod {11}$ I prefer this approach to reduce the base in
- calculus - Exponential Decay Question: The Half-Life of Cesium-137 is . . .
Exponential Decay Question: The Half-Life of Cesium-137 is 30 Years Suppose We Have a 100-mg Sample Ask Question Asked 10 years, 4 months ago Modified 10 years, 4 months ago
- Primes for which sum of sine ratios is nearly always an integer
Cite edited 17 hours ago Oscar Lanzi 51 4k 2 56 137 asked yesterday Integrand 7,784 16 50 78
- How do you calculate the modulo of a high-raised number?
I need some help with this problem: $$439^{233} \\mod 713$$ I can't calculate $439^{223}$ since it's a very big number, there must be a way to do this Thanks
- Upper and lower bounds - Mathematics Stack Exchange
By halving 5 (the number you are rounding to) = 2 5 Then to find the upper bound you add it to the number you are rounding so 135 + 2 5 = 137 5 ( this is a multiple of 5)
- geometry - What are the holosnubs of the regular polyhedra . . .
Snubbing usually is considered as vertex alternation, i e alternate vertices are maintained, the other ones get replaced by the sectioning facets underneath (which in case of vertex alternations then are nothing but the former's vertex figures) Whenever the pre-image contained an odd numbered polygon then surrounding that polygon by alternation rule, you'll come back in wrong parity Thence
- Polynomial system of equations over integers
Not that it helps in this case, but you can also subtract the equations, to get $ (y-1)^4- (x-1)^4=609$
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