- Solve # { (sqrtx (1-4x-y)=2), (sqrty (1+4x+y)=6):}# - Socratic
No real solutions Calling alpha = 4x+y we have { (sqrtx (1-alpha)=2), (sqrty (1+alpha)=6):} then 2 alpha = (1+alpha)^2- (1-alpha)^2=36 y-4 x or 4x+y = 9 y-1 x we
- What is the formula for the sequence #4,2,3,4,3,2,. . . # - Socratic
a_n = 1 120 (3 n^5-40 n^4+145 n^3+40 n^2-868 n+1200) If you want a formula for a sequence with these as the first six terms then you can proceed as follows: Write down the original sequence: color (blue) (4), 2, 3, 4, 3, 2 Write down a sequence formed by the differences of pairs of consecutive terms: color (blue) (-2), 1, 1, -1, -1 Write down a sequence formed by the differences of pairs of
- A triangle has sides A, B, and C. The angle between sides A . . . - Socratic
The length of side A is 10 145 (3dp) The angle between sides A and B is _c= pi 8=180 8=22 5^0 The angle between sides B and C is _a= pi 12=180 12=15^0 Given C=15; A=?
- Question #33eb8 - Socratic
First, subtract #color (red) ($145)# from each side of the equation to isolate the #w# term while keeping the equation balanced:
- If the measures of a triangle are 90°, 55°, and 3x - Socratic
=> x = 10 The measures (angles) of a triangle sum to 180^o =>90 + 55 + (3x+5) = 180 =>145 + (3x+5)=180 =>3x + 5 = 35 =>3x = 30 => x = 10
- Can you help me with finding perimeter of this sector fragment?
Just Q8 I'll ask more questions if I need more help
- Question #5b826 - Socratic
What we're really doing here is that we're given an initial state with # ["BrCl"]_i = "0 050 M"#, and we're given #K_ (eq)#, which is defined for a final state we define as equilibrium, when the rate of the forward reaction is equal to that of the reverse reaction
- Sans the lone satellite Luna, our planet Earth had cleared . . . - Socratic
Another (2015 TB 145 ) came a little beyond Moon's maximum apogee distance of 405400 km In view of all these findings, it is reasonable to admit that the Earth is yet to clear some NEOs like the asteroid (2016 RB1) that had come as close as 40000 km to the Earth
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