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- URL encoding the space character: + or %20? - Stack Overflow
As the aforementioned RFC does not include any reference of encoding spaces as +, I guess using %20 is the way to go today For example, "%20" is the percent-encoding for the binary octet "00100000" (ABNF: %x20), which in US-ASCII corresponds to the space character (SP)
- The origin on why %20 is used as a space in URLs
I am interested in knowing why '%20' is used as a space in URLs, particularly why %20 was used and why we even need it in the first place
- http - Spaces in URLs? - Stack Overflow
Since it's not mentioned anywhere in the grammar, the only way to encode a space is with percent-encoding (%20) In fact, the RFC even states that spaces are delimiters and should be ignored: In some cases, extra whitespace (spaces, line-breaks, tabs, etc ) may have to be added to break a long URI across lines
- OpenSSL Verify return code: 20 (unable to get local issuer certificate)
OpenSSL Verify return code: 20 (unable to get local issuer certificate) Asked 12 years, 11 months ago Modified 6 months ago Viewed 377k times
- android - How to access storage emulated 0 - Stack Overflow
Depending on amount of files on the phone it can take as 10-20 minutes to rebuild the media database as the service walks the phone directories, getting meta data, creating thumbnails, etc
- How to fix SyntaxWarning: invalid escape sequence in Python?
For convenience, you can use the following method to automatically add r to docstrings: write a script using e g libcst to parse the source code, modify it to add r at appropriate places, then write it back run the script on your code The advantage of using CST over AST is for example number of parentheses or white spaces are preserved
- NVM installation error on Windows. Cannot find the npm file
I searched and found that versions 23 10 0 and 16 20 2 are present in the folders of the same name C:\Users\KS\AppData\Local\nvm By analogy, I created a folder v0 12 2 and dropped the contents obtained during the installation of node-v0 12 2 Win-x64 msi into it
- Understanding The Modulus Operator - Stack Overflow
I understand the Modulus operator in terms of the following expression: 7 % 5 This would return 2 due to the fact that 5 goes into 7 once and then gives the 2 that is left over, however my confusion
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