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What is all of the real and imaginary zeros of #y= (x^2-9 . . . - Socratic
We have 4 zeros, 3 with multiplicity 3 and -3,3i and -3i with multiplicity of 1 y= (x^2-9) (x^2+9) (x-3)^2 = (x^2-3^2) (x^2- (3i)^2) (x-3)^2 = (x+3) (x-3) (x-3i) (x+
Question #d629b - Socratic
b) I multiply the 2 brackets: #4*7-4*3i+7*3i-3*3i^2=28-12i+21i+9=37+9i# Answer link
How do you evaluate (3a -9i +2ai +6) (a^2+9) + (3-9i+3i+9 . . . - Socratic
Explanation: The first thing we notice with the two expression here is that the denominators are the same since #a^2+9=9+a^2#
How do you solve 11x ^ { 2} + 10= 2x ^ { 2} - 15? | Socratic
x = +-5 3i Given: 11x^2+10 = 2x^2-15 Subtract the right hand side from the left to get: 9x^2+25 = 0 Now x^2 >= 0 for all real values of x, so this has no real solutions
How do you write the complex conjugate of the complex number 5-3i . . .
Explanation: Given a complex number #a+bi#, that number's complex conjugate, denoted #bar (a+bi)#, is given by
One solution of x^3+ (2-i)x^2+ (-4-3i)x+ (1+i)=0 is x=1+i. Find the . . .
One solution of x3 + (2 − i)x2 + (− 4 − 3i)x + (1 + i) = 0 is x = 1 + i Find the only positive real solution for x?
How do you divide (3i) (1+i) + 2 (2+3i) ? | Socratic
How do you divide 3i 1 + i + 2 2 + 3i? Precalculus Complex Numbers in Trigonometric Form Division of Complex Numbers 2 Answers Sihan Tawsik
For z_1 = -3 + 2i and z_2=4+3i, write z_1 z_2 in polar form. In which . . .
For #z_1 = -3 + 2i# and #z_2=4+3i#, write #z_1 z_2# in polar form In which quadrant will it lie in an Argand Diagram? Precalculus