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- Proof that the halting problem is NP-hard? - Stack Overflow
It is clear that any NP-complete problem can be reduced to this one While I agree that the halting problem is intuitively a much "harder" problem than anything in NP, I honestly cannot come up with a formal, mathematical proof that the halting problem is NP-hard
- NP-Hard Class - GeeksforGeeks
Many optimization problems in this domain, like optimizing approximation algorithms, can be NP-hard This implies that finding optimal solutions might be impractical, and researchers need to devise heuristic or approximation methods to get close-to-optimal results
- Does the halting problem belong to NP class of problems?
On the other hand, it is quite obviously NP-hard Given a different problem that is in NP, for example the "travelling salesman" problem, I can write a program that systematically generates all possible hints until it finds one that allows to solve the TSP instance
- NP-hardness - Wikipedia
In computational complexity theory, a computational problem H is called NP-hard if, for every problem L which can be solved in non-deterministic polynomial-time, there is a polynomial-time reduction from L to H
- NP-hard Problem: Understanding Computational Complexity
An NP-hard problem is one that is at least as difficult as the hardest problems in NP This article explains definitions, examples, and methods for dealing with NP-hard tasks
- Understanding NP-Hard Problems - numberanalytics. com
NP-hard problems are a class of problems that are at least as difficult as the hardest problems in NP (nondeterministic polynomial time) A problem is considered NP-hard if every problem in NP can be reduced to it in polynomial time
- Understanding P, NP, NP-Complete, and NP-Hard Problems: A . . . - Medium
NP-Hard problems may not even have a verifiable solution in polynomial time These problems are at least as hard as NP-Complete problems but may be even harder
- What makes an NP-hard problem not to be an NP-complete problem?
The halting problem is a decision problem, but it's not verifiable in polymonial time (the second requirement for a problem to be in NP by definition) that's why it cannot be NP-complete
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