- how to prove the chain rule? - Mathematics Stack Exchange
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- probability - Median for continuous distribution - Mathematics Stack . . .
Continuous Random Variable - Uniform Median, Exponential Mode 0 What is the difference between a
- is bounded linear operator necessarily continuous?
Added @Dimitris's answer prompted me to mention, beyond the fact that the implication on normed spaces indeed is an equivalence, that it's the converse which holds in the wider context of topological vector spaces, while the proposition mentioned here fails: there are bounded discontinuous linear operators, yet every continuous operator remains
- State space discretization - Mathematics Stack Exchange
If the continuous-time system is bounded input bounded output (BIBO) stable, then so is this exact discretized system If your input is not constant between sampling instances, then you could use a forward Euler discretization ( $\dot{x}(kT_s)\approx\frac{1}{T_s}(x_{k+1}-x_k)$ ) like @polfosol mentioned in his answer
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