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- [FREE] On a coordinate plane, triangle ABC and parallelogram GHJK are . . .
This answer is FREE! See the answer to your question: On a coordinate plane, triangle ABC and parallelogram GHJK are shown Triangle ABC has po… - brainly com
- [FREE] How does the area of triangle ABC compare to the area of . . .
The area of parallelogram GHJK = 8 square units Comparison: 6− 8 = −2 Thus, the area of triangle ABC is 2 square units less than the area of parallelogram GHJK
- [FREE] On a coordinate plane, triangle ABC and parallelogram GHJK are . . .
The calculations for the areas of triangle ABC and parallelogram GHJK are based on standard geometric formulas that are widely accepted and can be found in mathematics textbooks
- Three quadrilaterals exist such that GHJK ≅ ASDF and GHJK ≅ VBNM.
Here, three quadrilaterals GHJK,ASDF and GHJK are given such that, GH J K ≅ AS DF and GH J K ≅ V BNM Therefore, AS DF ≅ V BNM (by transitive property of congruence) And, if two shapes are congruent to each other then there corresponding sides and angles must be congruent That is, In quadrilaterals ASDF and VBNM, edges AS, SD, DF and FA are corresponding to VB, BN, NM and MV respectively
- I will mark the Brainliest answer. Please Help me! :)How does the area . . .
I will mark the Brainliest answer Please Help me! :) How does the area of triangle ABC compare to the area of parallelogram GHJK? A The area of ABC is 2 square units greater than the area of parallelogram GHJK B The area of ABC is 1 square unit greater than the area of parallelogram GHJK C The area of ABC is equal to the area of parallelogram GHJK D The area of ABC is 1 square unit
- [FREE] What is the final transformation in the composition of . . .
The final transformation that maps the pre-image GHJK to the image G'H"J"K" is a reflection across line m This is because a reflection flips the figure, which best explains the change in orientation of the points Thus, option B is correct
- [FREE] Trapezoid GHJK was rotated 180° about the origin to determine . . .
Rotating trapezoid GHJK 180° about the origin transforms each vertex's coordinates by changing their signs according to the formula (x′,y′) = (−x,−y) For accurate results, please provide the original coordinates of the trapezoid's vertices Once known, the new positions can be calculated easily using this transformation method
- Larissa is writing a coordinate proof to show that the diagonals of a . . .
Larissa is writing a coordinate proof to show that the diagonals of a square are perpendicular to each other She starts by assigning coordinates as given
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