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- What is the integral of 1 x? - Mathematics Stack Exchange
$\begingroup$ "Answers to the question of the integral of 1x are all based on an implicit assumption that the upper and lower limits of the integral are both positive real numbers" --- not completely correct: if they are both negative it also works This is an improper integral and does not converge in the remaining cases $\endgroup$ –
- calculus - Is there really no way to integrate $e^{-x^2 . . .
$\begingroup$ @user599310, I am going to attempt some pseudo math to show it: $$ I^2 = \int e^-x^2 dx \times \int e^-x^2 dx = Area \times Area = Area^2$$ We can replace one x, with a dummy variable, move the dummy copy into the first integral to get a double integral
- What is an integral number? - Mathematics Stack Exchange
In normal use, integral length would be equal to some integer, while unit length would be of length $1$ (see "unit number" here) Presumably the author meant, "in the unit ( with a different meaning! ) we use to measure lengths, these lengths are integer-valued"
- Newest integration Questions - Mathematics Stack Exchange
For questions about the properties of integrals Use in conjunction with (indefinite-integral), (definite-integral), (improper-integrals) or another tag(s) that describe the type of integral being considered This tag often goes along with the (calculus) tag
- How to calculate the integral in normal distribution?
It goes without saying that if you're trying to find a CDF, you need to add limits and evaluate the definite integral In the second equation you'll notice that I used "a" as the (upper) limit variable And the question is talking about the CDF, so the lower limit is negative infinity $\endgroup$ –
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