- What is a lambda expression, and when should I use one?
Here is another really good reference which explains very well what are lambda expressions in C++: Microsoft com: Lambda expressions in C++ I especially like how well it explains the parts of a lambda expression, in particular: the capture clause, parameter list, trailing-return-type, and lambda body
- How does generic lambda work in C++14? - Stack Overflow
Generic lambdas were introduced in C++14 Simply, the closure type defined by the lambda expression will have a templated call operator rather than the regular, non-template call operator of C++11 's lambdas (of course, when auto appears at least once in the parameter list) So your example: auto glambda = [] (auto a) { return a; }; Will make glambda an instance of this type: class * unnamed
- Lambdas: local variables need final, instance variables dont
Let be known that at least with the latest version of the compiler java 1 8 local variables only need to be effectively final so they don't need to be declared final per se but the cannot be modified
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