- verbs - log in to or log into or login to - English Language . . .
The difference between "log in to host com" and "log into host com" is entirely lexical, so it really only matters if you're diagramming the sentence Personally, I prefer to avoid prepositional phrases when possible, so I would write, "log into host com "
- Easy way to remember Taylor Series for log(1+x)?
Easy way to remember Taylor Series for log (1+x)? Ask Question Asked 10 years, 2 months ago Modified 5 years, 11 months ago
- Dividing logs with same base - Mathematics Stack Exchange
Dividing logs which have the same base changes the base of the log That is log a log b =logb a log a log b = log b a It doesn't matter what base we were using on the left hand side It will change the base of the log as above log 125 log 25 =log25 125 log 125 log 25 = log 25 125 and 253 2 = 125 25 3 2 = 125
- Which is correct? log in, log on, log into, log onto [duplicate]
For my money, log on to a system or log in to a system are interchangeable, and depend on the metaphor you are using (see comment on your post) I suppose there is a small bit of connotation that "log on" implies use, and "log in" implies access or a specific user
- The difference between log and ln - Mathematics Stack Exchange
The use of the "ln" abbreviation for natural logarithm is a bad thing because it makes people think that "log" is one thing and "ln" is another thing, and ask what's the difference between the two
- Using logging in correctly - English Language Usage Stack Exchange
There are a lot of questions concerning the correct use if login, log in, etc When speaking directly to an use I would say You can always change this permission by logging in in the internal do
- Logged-in, log-ined, login-ed, logined, log-in-ed, logged in?
49 Log in is a verb, while login is a noun Its Past Tense is logged in (I logged in yesterday) As an attributive phrase, it is logged-in (logged-in users)
- logarithms - Difference between $\log n$ and $\log^2 n$ - Mathematics . . .
Is there a difference between log n log n and log2 n log 2 n? EDIT: Follow up question: in terms of complexity , which would be faster, O(log n) O (log n) or O(log2 n) O (log 2 n)? My guess would be the first one (Note, this is not homework, I'm just trying to understand the difference between quicksort and bitonic sort on a hypercube topology )
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