- Question #7908b - Socratic
65 0 "g N"_2 Any time you want to convert between moles and grams of a substance, you must know that substance's molar mass, which is the mass of one mole of that substance (One mole is equal to Avogadro's number (6 022xx10^23) of individual particles molecules of that substance ) To find the molar mass of a nitrogen molecule, we'll first realize its chemical formula, which is "N"_2 Most
- How should I study about moles and how they relate to things like . . .
It was natural to assign to each atom an atomic mass that had the same number as the mass of its mole Thus, the atomic masses became 1 unit for "H", 12 units for "C", and 16 units for "H" Eventually, chemists figured out how many atoms there are in a mole of atoms, and they called it Avogadro's Number (N_"A")
- Question #4bd54 - Socratic
The balanced equation tells us that 1 mole of Oxygen react with 1 mole of Carbon; we shall multiply by that conversion factor:
- Question #ef39d - Socratic
4 53 * 10^ (9)"kJ mol"^ (-1) The first thing you need to do here is to figure out the frequency of the gamma-ray photons As you know, wavelength and frequency have an inverse relationship as given by the equation color (blue) (ul (color (black) (nu * lamda = c))) Here lamda is the wavelength of the wave c is the speed of light in a vacuum, usually given as 3 * 10^8"m s"^ (-1) Rearrange the
- Question #bfcbb - Socratic
Copper has a molar mass of 63 546 g mol−1, which means that 1 mole of copper has a mass of 63 546 g Now, in order to have 1 mole of copper, you need to have 6 022 ⋅ 1023 atoms of copper → this is known as Avogadro's constant So, right from the start, you can say that if 1 mole of copper has a mass of 63 546 g and 1 mole of copper contains 6 022 ⋅ 1023 atoms of copper, then 6 022 ⋅
- How many helium atoms in a #20*mol# quantity of this gas?
And thus the mole is the link between the micro world of atoms and molecules, which we cannot see, but whose existence we can infer, to the macro world of grams, and kilograms, and litres 6 022xx10^23, -=N_A, "the Avocado number", is the number of particles in one mole
- Question #5c1f1 - Socratic
157 48" g" Given: (1 45xx10^24" atoms of Zn") 1 Multiply by the conversion factor for the Avogadro constant : (1 45xx10^24" atoms of Zn") 1(1" mole of Zn") (6 02xx10^23" atoms of Zn") Please observe how the conversion factor cancels the units "atoms of Zn" and we are left with the units "moles of Zn": (1 45xx10^24cancel(" atoms of Zn")) 1(1" mole of Zn") (6 02xx10^23cancel(" atoms of Zn
- Question #bb0ad - Socratic
In your case, you know that #1# mole of ammonia reacts with #1# mole of oxygen gas The fact that you have equal numbers of moles of the two reactants and a #4:5# mole ratio between them tells you that you're dealing with a limiting reagent
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