How to find nPr (permutations) efficiently? - Stack Overflow 4 How about this: nPr = (n−1)Pr + (n−1)P (r−1) ⋅ r Rationale: nPr denotes the number of ways to choose r elements from n while noting their order and not putting them back In the above recursion I distinguish two cases Either you don't choose the n th element, in which case you'll be choosing all your r elements from a set of (n−1)
kubernetes - kubectl logs - continuously - Stack Overflow kubectl logs lt;pod-id gt; gets latest logs from my deployment - I am working on a bug and interested to know the logs at runtime - How can I get continuous stream of logs ? edit: corrected quest
What are all of the Maven Command Line Options? - Stack Overflow I'm looking for the list of options for Maven 2 2 but cannot find it If someone knows the location please post it Thank you I found the following but I don't know enough of Maven to know which a
NPR ran a prepper episode last Friday. . . | Survivalist Forum Chased down a link for you all Can you really 'prep' for the breakdown of society? For anywhere from $100 to $3,000 or more, you can get ready for doomsday with a prepper kit Michael Mills, lecturer in criminology at the University of Kent, joins host Krys Boyd to discuss the phenomenon of
counting combinations and permutations efficiently I have some code to count permutations and combinations, and I'm trying to make it work better for large numbers I've found a better algorithm for permutations that avoids large intermediate resu