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Windows版QQ9的聊天记录导出支持导入旧版文件、导出到手机或从手机导出，具体操作需参考设置选项。
- 谁来说明一下新版 qq NT 架构是个什么东西? - 知乎
NT 架构，基于 Electron 开发。 Electron 是一个使用 JavaScript、HTML 和 CSS 构建跨平台的桌面应用程序，它基于 Node js 和 Chromium，被 Atom 编辑器和许多其他应用程序使用，可以兼容 Windows 、Mac和 Linux系统，构建出三个平台的应用程序。
- iis - SQL Server Login error: Login failed for user NT AUTHORITY . . .
Login failed for user 'NT AUTHORITY\SYSTEM' I tried to add NT AUTHORITY SYSTEM to SSMS (SQL Server Management Studio) logins, but it was already a principal, showing the following error:
- The difference between the Local System account and the Network . . .
NT_AUTHORITY\LocalService (aka the Local Service account), or NT AUTHORITY\NetworkService (aka the Network Service account) That capability only was added with Task Scheduler 2 0, which only exists in Windows Vista Windows Server 2008 and newer A service running as NetworkService presents the machine credentials on the network
- security - SQL Server returns error Login failed for user NT . . .
The client application uses a hard-coded connection string with Integrated Security=True, but when the applications attempts to create a connection to the database, it throws an SQLException saying "Login failed for user 'NT AUTHORITY\ANONYMOUS LOGON" I can log on to the database through Management Studio on this account without problem
- 为什么 Windows 11 仍然在使用 Windows 10 的 NT 10 内核? - 知乎
因此，如果没有兼容性问题，Windows 7的内核版本就是NT 7 0，其实也就是OS版本（winver的信息可以表示一切）。 所以你看到，Windows 10的NT版本号是10 0，没有任何问题。 好了，讲明白“所谓的内核版本号就是OS版本号”这个事实后，我还需要在这里阐述一个事实。
- smbclient NT_STATUS_ACCESS_DENIED - Stack Overflow
smbclient NT_STATUS_ACCESS_DENIED Asked 10 years, 11 months ago Modified 1 year, 10 months ago Viewed 95k times
- Getting the Username from the HKEY_USERS values - Stack Overflow
3 The proper way to do this requires leveraging the SAM registry hive (on Windows 10, this requires NT AUTHORITY\SYSTEM privileges) The information you require is in the the key: HKEY_LOCAL_MACHINE\SAM\SAM\Domains\Account\Users\Names Each subkey is the username, and the default value in each subkey is a binary integer
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