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- Whats the size of a QWORD on a 64-bit machine? - Stack Overflow
So far I found people saying, that the word size refers to the size of a processor register, which would suggest on a 64-bit machine the word size being 64 bits and thus a QWORD (4 * word) being 256 bits in size
- For Windows MSVC, where is the QWORD data type defined?
There is a 64-bit DWORDLONG type but that name is even sillier than DWORD See Windows Data Types It mentions QWORD but doesn't say where it is defined!
- How to read QWORD (64-bit) from the registry in C++?
How do I read a REG_QWORD from the registry? Most specifically the HardwareInformation qwMemorySize I found that with it divided by 1024 then once again divided by 1024 you can get the Video memo
- What does qword ptr [hexvalue] mean without a base register
The QWORD PTR is just a size specifier (redundant here, but it improves readability), it is not related with having a base register If you really are interested into the various addressing modes the CPU have, you can read the Intel Manuals (Google that)
- x86 - What do these assembly lines mean? - Stack Overflow
I am struggling on a homework because I do not understand what these lines are supposed to mean ? mov rax, qword ptr [rbp - 0x28] mov rax, qword ptr [rax] mov eax, dword ptr [rax] mov dword ptr [rb
- What does mov qword ptr ds: [rax+18], r8 mean?
Commas are simply operand separators, indicating the first operand has ended and the second is about to begin r8 mov qword ptr ds:[rax+18], r8 Compared to the first operand, the second one is a piece of cake This simply means the value currently in register r8 is the source value, and what will be assigned to the address rax+18
- Understanding assembly code: mov dword and mov qword in main. c
0x555555554601 <main+7> mov qword ptr [rbp - 0x10], rsi 0x555555554605 <main+11> mov eax, 0x2a 0x55555555460a <main+16> pop rbp 0x55555555460b <main+17> ret edi stores argc a 32 bit value - packed in a 64 bit boundary with the upper 32 bits of no use for you
- QWORD Storing implementing using 32-bit REGs. ?
Given that variable I is defined as Qword, the equation I = 2*I can be implemented using the following minimal instructions: the solution : MOV EAX, DWORD PTR I ADD DWORD PTR I, EAX what i dont g
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