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- What does . shape [] do in for i in range (Y. shape [0])?
shape is a tuple that gives you an indication of the number of dimensions in the array So in your case, since the index value of Y shape[0] is 0, your are working along the first dimension of your array
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Pandas Dataframe ValueError: Shape of passed values is (X, ), indices imply (X, Y) Asked 11 years, 9 months ago Modified 7 years, 5 months ago Viewed 60k times
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You can think of a placeholder in TensorFlow as an operation specifying the shape and type of data that will be fed into the graph placeholder X defines that an unspecified number of rows of shape (128, 128, 3) of type float32 will be fed into the graph a Placeholder does not hold state and merely defines the type and shape of the data to flow
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I am trying to add a shape at a specific cell location but cannot get the shape added at the desired location for some reason Below is the code I am using to add the shape: Cells(milestonerow,
- How can I get a list shape without using numpy? - Stack Overflow
You'll need to complete a few actions and gain 15 reputation points before being able to upvote Upvoting indicates when questions and answers are useful What's reputation and how do I get it? Instead, you can save this post to reference later
- How do I get the picture size with PIL? - Stack Overflow
How do I get a size of a pictures sides with PIL or any other Python library?
- python - ValueError: shape mismatch: objects cannot be broadcast to a . . .
ValueError: shape mismatch: objects cannot be broadcast to a single shape It computes the first two (I am running several thousand of these tests in a loop) and then dies
- python - Numpy array dimensions - Stack Overflow
A piece of advice: your "dimensions" are called the shape, in NumPy What NumPy calls the dimension is 2, in your case (ndim) It's useful to know the usual NumPy terminology: this makes reading the docs easier!
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