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- Question #b1cc9 - Socratic
Point B (-1 6,-2 1) x-3y = 5 Eqn (1) 3y = x - 5 y = x 3 - 5 3 Slope m = 1 3 Slope of perpendicular line = -1 m = -3 Equation of AB is y - -3 = -3 (x - -1) y + 3x = -6 Eqn (2) Solving Eqns (1), (2) 10x = -13, x = -1 3 y = -2 1# Mid point (-1 3,-2 1) Point B (-1 6, -1 2)
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Forum for Y8 Games A place for players to meet and discuss about gaming related topics
- Question #dec41 - Socratic
Explanation: The equation of a line in #color (blue)"point-slope form"# is
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connecting x 3 basketball x 2 sense-of-unity-game x 2 slope x 7 papalouie x 6 drift x 2 horror x 7
- Question #bccac - Socratic
Explanation: Given the slope of a line and a point on it, we can write its equation in point-slope form, denoted by:
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For players to talk about games and other general topics
- Question #a77d0 - Socratic
The way to solve this question is to first find the slope using the two points given and then use that slope like you would in point slope form The Final equation : #y + 2 = 2x - 12#
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