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- How do you find a standard form equation for the line with (5,3); slope . . .
The standard form equation for this line is 4x -y = -23 Putting the provided slope and point coordinates into the point-slope form of a line will allow us to transform the equation into standard form Point-slope form is y - y-sub-1 = m(x + x-sub-1) I am using -sub-1 to indicate a sub scripted number 1 I couldn't make the 1 sub scripted The sub scripted y and x refer to the given point
- What is the slope and y-intercept of y=2x-2? - Socratic
The slope is 2 The y-intercept is at (0,-2) The equation is in y=mx+b form So, the m is the slope and the b is the y-intercept
- How do you find the slope and y intercept of - Socratic
Slope: -1 Y intercept: 4 Rearrange the equation so that it is written in slope intercept form: y=mx+b Where m is the slope and b is the y intercept 2x+2y=8 Begin to isolate y by subtracting 2x on both sides of the equation 2y=-2x+8 Isolate y by dividing both sides of the equation by @2@ y=-x+4 Where the slope is -1 and the y intercept is 4
- How do you graph -6x+9y=-18? - Socratic
-6x+9y=-18 This is a linear equation, because the equation does not have any exponents Graph it by putting the equation into either slope-intercept form y=mx+b or point-slope form y-y_1=m(x-x_1) Isolate y by first adding 6x to each side: 9y=6x-18 Divide each side by 9: y=2 3x-2 Now graph the line y=2 3x-2 by first plotting the y intercept at (0,-2), then connecting points with a slope of 2 3
- The normal (2ap, ap^2) to the parabola x^2=4ay meets the . . . - Socratic
Again the slope of the normal as it joins #(2ap,ap^2) and (2aq,aq^2)# is also
- How do you graph using slope and intercept of - Socratic
See below So we want it in slope which is y=mx+b but this is in standard form So let start by rewriting the equation 2x-y=5 Now, we subtract 2x from both sides which gives us: -y=-2x+5 Now, the variable y can never be a negative numbers, so we divide everything by negative one which changes the sign to this: y=2x-5 Now, you can plug in any numbers for x that gives you an input for y So let
- How does y=mx+b work? | Socratic
See below y=mx+b is the slope intercept form of an equation describing a line So how do we use it? The first part of the equation I want to look at is the x and y: for any value of x I choose to put into the equation, I will get a resulting y For instance, let's say x=0 and it works out that y=2 - I'd have a point I could plot on graph If I do that one more time, say like x=1, y=3, and I
- How do you find the slope for 5x-4y=20? - Socratic
How does change in the slope affect the steepness of a line? Why is the slope of a horizontal line is zero? How do you determine the slope of #(3, –5)# and #(–2, 9)#?
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