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  • How do you find a standard form equation for the line with (5,3); slope . . .
    Putting the provided slope and point coordinates into the point-slope form of a line will allow us to transform the equation into standard form Point-slope form is y - y-sub-1 = m (x + x-sub-1)
  • What is the slope and y-intercept of y=2x-2? | Socratic
    The slope is 2 The y-intercept is at (0,-2) The equation is in y=mx+b form So, the m is the slope and the b is the y-intercept
  • How do you find the slope and y intercept of - Socratic
    Slope: -1 Y intercept: 4 Rearrange the equation so that it is written in slope intercept form: y=mx+b Where m is the slope and b is the y intercept 2x+2y=8 Begin to isolate y by subtracting 2x on both sides of the equation 2y=-2x+8 Isolate y by dividing both sides of the equation by @2@ y=-x+4 Where the slope is -1 and the y intercept is 4
  • How do you find the slope and intercept of - Socratic
    Explanation: the equation of a line in slope-intercept form is ∙ xy = mx + b where m is the slope and b the y-intercept rearrange 2x + 5y = 10 into this form subtract 2x from both sides 2x −2x + 5y = − 2x +10 ⇒ 5y = − 2x +10 divide all terms by 5 ⇒ y = − 2 5x +2 ← in slope-intercept form with slope = − 2 5 and y-intercept = 2
  • How do you graph -6x+9y=-18? | Socratic
    Graph it by putting the equation into either slope-intercept form y = mx + b or point- slope form y −y1 = m(x − x1) Isolate y by first adding 6x to each side: 9y = 6x −18 Divide each side by 9: y = 2 3x − 2 Now graph the line y = 2 3 x − 2 by first plotting the y intercept at (0, − 2), then connecting points with a slope of 2 3
  • How do you graph using slope and intercept of - Socratic
    See below So we want it in slope which is y=mx+b but this is in standard form So let start by rewriting the equation 2x-y=5 Now, we subtract 2x from both sides which gives us: -y=-2x+5 Now, the variable y can never be a negative numbers, so we divide everything by negative one which changes the sign to this: y=2x-5 Now, you can plug in any numbers for x that gives you an input for y So let
  • The normal (2ap, ap^2) to the parabola x^2=4ay meets the . . . - Socratic
    (a)Given equation of the parabola x^2=4ay => (dy) (dx)=1 (4a)*2x=x (2a) Slope of the normal m=-1 [ (dy) (dx)]_ (2ap,ap^2)=- (2a) (2ap)=-1 p Again the slope of
  • How does y=mx+b work? | Socratic
    See below y=mx+b is the slope intercept form of an equation describing a line So how do we use it? The first part of the equation I want to look at is the x and y: for any value of x I choose to put into the equation, I will get a resulting y For instance, let's say x=0 and it works out that y=2 - I'd have a point I could plot on graph If I do that one more time, say like x=1, y=3, and I




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