Solve the recurrence: T(n)=2T(n 2)+n logn - Stack Overflow When you start unrolling the recursion, you will get: Your base case is T(1) = 1, so this means that n = 2^k Substituting you will get: The second sum behaves the same as harmonic series and therefore can be approximated as log(k) Now that k = log(n) the resulting answer is:
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algorithm - Solve: T (n) = T (n-1) + n - Stack Overflow In Cormen's Introduction to Algorithm's book, I'm attempting to work the following problem: Show that the solution to the recurrence relation T(n) = T(n-1) + n is O(n2 ) using substitution (Ther
Reading output with telnetlib in realtime - Stack Overflow I'm using Python's telnetlib to telnet to some machine and executing few commands and I want to get the output of these commands So, what the current scenario is - tn = telnetlib Telnet(HOST) tn
Complexity of the recursion: T (n) = T (n-1) + T (n-2) + C I want to understand how to arrive at the complexity of the below recurrence relation T(n) = T(n-1) + T(n-2) + C Given T(1) = C and T(2) = 2C; Generally for equations like T(n) = 2T(n 2) + C (Gi