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K_ {sp} of salt A_3B_2, solubility x ,mol ,L^ {-1}, is: - Toppr
If x mol L−1 is the solubility of KAl(SO4)2, then Ksp is equal to:
1 mol of ferric oxalate is oxidized by x mol of - Toppr
1 mol of ferric oxalate is oxidised by x mol of M nO4− in acidic medium The ratio x y is :
1 mol of ferric oxalate is oxidised by x mol of Mn {O}_ {4 . . . - Toppr
16 x moles of potassium dichromate oxidises 1 mol of ferrous oxalate in acidic medium here x is
1 mol of ferric oxalate is oxidized by x mol of MnO . . . - Toppr
1 mol of ferric oxalate is oxidized by x mol of M nO⊝ 4 in acidic medium Hence, the value of x is: 1 2 1 6 1 8 1 5
The solubility of A_ {2}X_ {3} is y mol dm^ {-3}. Its solubility . . .
Solubility of salt M 2X3 is y mol dm−3 The solubility product of the salt will be:
The solubility of calcium phosphate in water is x mol - Toppr
The solubility of calcium phosphate in water is x mol L−1 at 25oC Its solubility product is equal to 108x2 36x3 108x5 36x5
The concentration of oxalic acid is X mol lit^ {-1}. 40 mL of this . . .
The concentration of oxalic acid is ′X′ mol lit−1 40 mL of this solution reacts with 16 mL of 0 05 M acidified KM nO4 What is the pH of ′X′ M oxalic acid solution?
If the solubility of lithium sodium hexafluoro aluminate,
The solubility of lithium sodium hexafluoroaluminate, Li3N a3(AlF 6)2 is a mol litre−1 Its solubility product is equal to:
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