- Why does Co2+ have 7 electrons in the 3d orbital, and not 5 like Mn?
Why does Co2+ have 7 electrons in the 3d orbital, and not 5 like Mn? Ask Question Asked 11 years, 4 months ago Modified 7 years, 3 months ago
- Is carbon dioxide slightly or highly soluble in water?
Carbon dioxide content in air is only 0 03%, but it is highly soluble in water unlike oxygen and one volume of CO2 dissolves in equal volume of water, the solubility being higher at low temperature From European Environment Agency: Carbon dioxide is a colourless, odourless gas, denser than air that occurs naturally in the earth's atmosphere
- How much do you pay for a CO2 tank? Refill? - Homebrew Talk
My LHBS is quoting me about $180 for a 10 lb CO2 tank, with $40 refills; they want $50 for a used keg as well Is it me, or are they screwing me?
- Why is carbon dioxide considered a Lewis acid?
$\ce {CO2}$ is considered a Lewis acid How it is an acid? According to Lewis: “species that accept an electron pair are acids” But $\ce {CO2}$ can't accept electron pairs because oxygen and carbon
- Baking Soda + Citric Acid + Water = CO2, how much though?
Baking soda (sodium bicarbonate) + citric acid react when mixed with water to form some amount of carbon dioxide gas ($\ce {CO2}$) I am trying to determine what percentage of the products is carbon dioxide: in other words, how much does reaction make?
- Reaction between NaOH and CO2 - Chemistry Stack Exchange
So I wanted to know what the reaction between sodium hydroxide and carbon dioxide can be, and upon research I got 2 answers The first one is $$\\ce{CO2 + NaOH(aq) - gt; NaHCO3(aq)}$$ and the seco
- Does CO2 dissolve in water? - Chemistry Stack Exchange
The amount of CO2 dissolved in water is proportional to the outer pressure At 20°C, 1 liter water dissolves about 1 7 g CO2 at normal pressure (1 atm) If the pressure is twice as large, the amount of dissolved CO2 is twice as much, 3 4 g
- reaction mechanism - Why NaOH (s,l) + CO2 (g) → Na2CO3 (s)? Why not . . .
$\ce {2NaOH + CO2 <=> Na2CO3 + H2O}$ tends to favor more gas molecules with fewer atoms apiece, which is seen to be the left side (the sodium compounds, even if ionic, exist in the gas phase as neutral clusters of said ions)
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