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- Decrement in Java - Stack Overflow
The value of the expression result-- is a copy of result, it is defined before the decrementing That's why it's called post -decrement After the value of the expression result-- is defined, result is decremented But: Right after this, the value of result is overriden by the value of the result-- expression (result = 5), which was 5
- c - Increment and Decrement Operators - Stack Overflow
Postfix decrement (x--) is different from prefix decrement (--x) The former return the value x, then decrements it; the latter decrements and then returns the value
- Behaviour of increment and decrement operators in Python
Behaviour of increment and decrement operators in Python Asked 16 years, 2 months ago Modified 1 year, 10 months ago Viewed 1 6m times
- syntax - Why avoid increment (++) and decrement (--) operators in . . .
The ++ (increment) and -- (decrement) operators have been known to contribute to bad code by encouraging excessive trickiness They are second only to faulty architecture in enabling to viruses and other security menaces
- How to increment a pointer address and pointers value?
First, the ++ operator takes precedence over the * operator, and the () operators take precedence over everything else Second, the ++number operator is the same as the number++ operator if you're not assigning them to anything The difference is number++ returns number and then increments number, and ++number increments first and then returns it Third, by increasing the value of a pointer
- Change for loop increment decrement value - Stack Overflow
Instead of "decrement by 0 3", you can use the integer loop counter , and then multiply current value by 0 3 to use in whatever calculation you mean to use it in Having a floating point loop counter raises issues with exact comparison for the loop condition (e g 0 3 - 0 3 may give 0 00000000001 which tests greater than zero)
- What is the difference between prefix and postfix operators?
The value of i++ is i The prefix decrement increases the value of its operand before it has been evaluated The value of --i is i - 1 Prefix increment decrement change the value before the expression is evaluated Postfix increment decrement change the value after So, in your case, fun(10) returns 10, and printing --i prints i - 1, which is 9
- Why is the -- operator not subtracting from the value when executed . . .
It will get executed [decrement the value] after the assignment = operator has finished its execution with the existing value To be clear, in case of post decrement, the -- operator is evaluated and the decrement is scheduled once the other evaluations including that operand are finished
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