- What is the formula of #magnesium hydroxide#? - Socratic
Mg(OH)_2 Now we know that hydroxides are salts of HO^-, and some metal ion Now if the parent metal has an electronic configuration of 2:8:2, then there are 12 electrons, and the atomic number of the metal is equal to 12 We look on the Periodic Table, and we find that Z=12, for "magnesium metal" As a Group 2 metal, magnesium forms a Mg^(2+) ion, and hence its hydroxide is Mg(OH)_2
- What makes for a good leaving group? + Example - Socratic
A good leaving group has to be able to part with its electrons easily enough, so typically, it must be a strong acid or weak base relative to other substituents on the same molecule It helps to know the pKa of what would be leaving Let's say you had a mechanism where you are trying to do an E2 reaction to make an -OH (hydroxyl) group leave Maybe you have this compound on hand, sec-butanol
- What is the chemical formula for lithium hydroxide? - Socratic
LiOH Lithium is a Group 1 metal and commonly forms a M^+ ion Hydroxide anion, ""^(-)OH, has a unit negative charge When they make music together, there is thus 1:1 stoichiometry between ions: Li(s) + H_2O(l) rarr LiOH(aq) + 1 2H_2(g)uarr
- What is the value of ΔG°cell? - Socratic
They have a cadmium anode, which is oxidized to Cd(OH)2(s) in a basic background electrolyte of concentrated OH–, and a cathode half-reaction in which NiO(OH)(s) is reduced to Ni(OH)2(s) Cd(OH)2 +2e^- -> Cd +2OH- E^o red = -0 403V
- Question #6b9a2 - Socratic
"a " 0 02 "mol" "b " 0 89 "g" In order to answer these questions we first need to know the equation representing this chemical reaction
- Why does neutralisation of any strong acid in an aqueous . . . - Socratic
Because its the same reaction A monobasic [monoprotic] acid like HCl has one H atom, which fully dissociates to form a hydrogen ion, H^+ The strong alkali fully dissociates to forman hydroxide ion OH^-, which react to from water This is the ionic equation for neutralisation and occurs for all strong acid strong alkali reactions
- If 50. 0 milliliters of 3. 0 M H_3PO_4 completely . . . - Socratic
Mg(OH)_2(s) +H_3PO_4(aq) rarr Mg^(2+)HPO_4^(-)(aq) + 2H_2O(l) With respect to phosphoric acid, we got a molar quantity of 3 0*mol*L^-1xx50xx10^-3*L-=0 150*mol And thus we SUPPOSE it to have neutralized 0 0750*mol magnesium hydroxide which was ostensibly present in a 150*mL volume
- Question #7f6cb - Socratic
I'd go for no reaction, but I suspect that the answer is 4 dissociation Potassium chloride, "KCl", and sodium hydroxide, "NaOH", are both soluble ionic compounds, so you can expect them to exist as ions in aqueous solution
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