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- operators - What does =~ do in Perl? - Stack Overflow
51 I guess the tag is a variable, and it is checking for 9eaf - but does this exist in Perl? What is the "=~" sign doing here and what are the " " characters before and after 9eaf doing?
- What is the meaning of @_ in Perl? - Stack Overflow
128 perldoc perlvar is the first place to check for any special-named Perl variable info Quoting: @_: Within a subroutine the array @_ contains the parameters passed to that subroutine More details can be found in perldoc perlsub (Perl subroutines) linked from the perlvar: Any arguments passed in show up in the array @_
- operators - What is the difference between || and or in Perl . . .
53 From Perl documentation: OR List operators On the right side of a list operator, it has very low precedence, such that it controls all comma-separated expressions found there
- Whats the use of lt; gt; in Perl? - Stack Overflow
@pst, <> is not a file handle, "null" or otherwise It's an operator Specifically, the readline operator There's a reference to it as the "angle operator" in perlvar, although there isn't actually any such operator The angle brackets are used by two operators: readline or glob The operator depends on the contents of the brackets
- How can I parse command-line arguments in a Perl program?
I'm working on a Perl script How can I parse command line parameters given to it? Example: script pl "string1" "string2"
- operators - What does =~ mean in Perl? - Stack Overflow
25 =~ is the Perl binding operator It's generally used to apply a regular expression to a string; for instance, to test if a string matches a pattern:
- Perl: Use s (replace) and return new string - Stack Overflow
In Perl, the operator s is used to replace parts of a string Now s will alter its parameter (the string) in place I would however like to replace parts of a string befor printing it, as in pri
- How do I perform a Perl substitution on a string while keeping the . . .
In Perl, what is a good way to perform a replacement on a string using a regular expression and store the value in a different variable, without changing the original? I usually just copy the string to a new variable then bind it to the s regex that does the replacement on the new string, but I was wondering if there is a better way to do this?
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