- What is the difference between == and === in Verilog?
Some data types in Verilog, such as reg, are 4-state This means that each bit can be one of 4 values: 0,1,x,z This means that each bit can be one of 4 values: 0,1,x,z With the "case equality" operator, === , x's are compared, and the result is 1
- What is the difference between = and lt;= in Verilog?
<= is a nonblocking assignment It is used to describe sequential logic, like in your code example Refer to IEEE Std 1800-2012, section 10 4 2 "Nonblocking procedural assignments"
- verilog - What is `+:` and `-:`? - Stack Overflow
Normal part selects in Verilog require constants So attempting the above with something like dword[i+7:i] is not allowed So if you want to select a particular byte using a variable select, you can use the indexed part select
- lt;= Assignment Operator in Verilog - Stack Overflow
"<=" in Verilog is called non-blocking assignment which brings a whole lot of difference than "=" which is called as blocking assignment because of scheduling events in any vendor based simulators It is Recommended to use non-blocking assignment for sequential logic and blocking assignment for combinational logic, only then it infers correct
- verilog - What is the difference between single ( ) and double . . .
This isn't quite correct In Verilog, a vector (or any other) object is 'true' if it is non-zero, and it is known - in other words, it does not contain x z metavalues So, it's not 'tested for equality to 0' @VL: try not to combine Verilog and SV questions - they're different languages You wouldn't ask a C question in a C++ group, or vice-versa
- operator in verilog - Stack Overflow
i have a verilog code in which there is a line as follows: parameter ADDR_WIDTH = 8 ; parameter RAM_DEPTH = 1 << ADDR_WIDTH; here what will be stored in RAM_DEPTH and what does the << operator do here
- Verilog ** Notation - Stack Overflow
Double asterisk is a "power" operator introduced in Verilog 2001 It is an arithmetic operator that takes left hand side operand to the power of right hand side operand In other words, X ** Y raises X to the power of Y
- verilog - Order of bits in reg declaration - Stack Overflow
If I need to use 4 8-bit numbers, I would declare the following reg: reg [7:0] numbers [3:0] I'm quite confused about the difference between the first and second declaration ([7:0] and [3:0])
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