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How much zeros has the number $1000!$ at the end? 1 If a number ends with n n zeros than it is divisible by 10n 10 n, that is 2n5n 2 n 5 n A factorial clearly has more 2 2 s than 5 5 s in its factorization so you only need to count how many 5 5 s are there in the factorization of 1000! 1000!
Infected Dinner Brainteaser - Mathematics Stack Exchange I came across this brainteaser online that I found quite confusing: There are $1000$ people having dinner at a grand hall One of them is known to be sick, while the other $999$ are healthy Each m
Find the number of times - Mathematics Stack Exchange Question: Find the number of times 5 5 will be written while listing integers from 1 1 to 1000 1000 Now, it can be solved in this fashion The numbers will be of the form: 5xy, x5y, xy5 5 x y, x 5 y, x y 5 where x, y x, y denote the two other digits such that 0 ≤ x, y ≤ 9 0 ≤ x, y ≤ 9 So, x, y x, y can take 10 10 choice each
probability of an event occuring with numerous attempts Often in calculating probabilities, it is sometimes easier to calculate the probability of the 'opposite', the technical term being the complement Because if something happens with probability p p, then it does not happen with probability 1 − p 1 p, e g if something happens with probability 0 40 0 40 (40% 40 %) then it does not happen with probability 1 − 0 40 = 0 60 1 0 40 = 0 60 (60%
algebra precalculus - Multiple-choice: sum of primes below $1000 . . . For example, the sum of all numbers less than 1000 1000 is about 500, 000 500, 000 So, 168 1000 × 500, 000 168 1000 × 500, 000 or 84, 000 84, 000 should be in the right ballpark 76127 76127 is the right answer, by this reasoning