1000 ISLANDS ELECTRONICS INCBusiness Directories,Company Directories

Company Name: Corporate Name:	1000 ISLANDS ELECTRONICS INC
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Company Address:	2131 Parkedale Ave,BROCKVILLE,ON,Canada
ZIP Code: Postal Code:	K6V5V6
Telephone Number:	6133422566
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USA SIC Code(Standard Industrial Classification Code):	573103
USA SIC Description:	Television & Radio-Dealers
Number of Employees:	1 to 4
Sales Amount:	$500,000 to $1 million
Credit History: Credit Report:	Very Good
Contact Person:	George Perera
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Last two digits of $2^ {1000}$ via Chinese Remainder Theorem?
For the congruence modulo $4$ you don't even need to invoke Euler's Theorem; you can just note that since $2^2\equiv 0\pmod {4}$, then $2^ {1000}\equiv 0 \pmod {4}$
Keep rolling two dice until the cumulative sum hits 1000
Keep rolling two dice until the cumulative sum hits 1000 Ask Question Asked 2 years, 3 months ago Modified 2 years, 3 months ago
Solving for the last two digits of a large number $3^ {1000}$?
I found this question asking to find the last two digits of $3^{1000}$ in my professors old notes and review guides What material must I know to solve problems like this with remainders I know W
How much zeros has the number $1000!$ at the end?
1 the number of factor 2's between 1-1000 is more than 5's so u must count the number of 5's that exist between 1-1000 can u continue?
Infected Dinner Brainteaser - Mathematics Stack Exchange
I came across this brainteaser online that I found quite confusing: There are $1000$ people having dinner at a grand hall One of them is known to be sick, while the other $999$ are healthy Each m
Prove $1. 01^ {1000} gt; 1000$ without using calculator
Prove $1 01^ {1000} > 1000$ without using calculator With WolframAlpha $1 01^ {1000} \approx 20959$, but can this be proved without calculator?
statistics - If I ask $1000$ people to choose a random number between . . .
Imagine I asked $1000$ people to choose a number between $0$ and $999$ (both inclusive, the numbers are not biased, they will be completely random) and write that number down Now, after that, pick a
elementary number theory - How to find the last digit of $3^ {1000 . . .
The last digit of $3^5$ is $3$ The last digit of $3^6$ is $9$ Notice a pattern? Why does this pattern exist? What is going on when I multiply by three? Based on this we could guess that it has a period of $4$ so that $3^ {4n}\equiv 1$ Use this to find the last digit of $3^ {1000}$ (Do you know modular arithmetic? If so it is a lot easier)
limits - Finding greatest element in series $1000^n n!$ - Mathematics . . .
Finding greatest element in series $1000^n n!$ Ask Question Asked 9 years ago Modified 9 years ago
Find the number of times $5$ will be written while listing integers . . .
Alternate Method: We want to count the number of times the digit $5$ appears in the list of positive integers from $1$ to $1000$