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How do you find the zeros of f(x) = 3x^4 +4x^3 +6x^2 -4 . . . - Socratic Use a numerical method to find approximate zeros: x_1 ~~ -0 908845148702144 x_2 ~~ 0 639396468497863 x_ (3,4) ~~ -0 53194232656453+-1 41826916487156i f (x) = 3x^4+4x^3+6x^2-4 By the rational root theorem, any rational zeros of f (x) are expressible in the form p q for integers p, q with p a divisor of the constant term -4 and q a divisor of the coefficient 3 of the leading term That means
Write an equation of the line in standard form? - Socratic 6x −y = 5 is a linear equation in standard form: Ax +Bx = C We can find the slope by converting it to slope-intercept form: y = mx + b, where m is the slope To convert the equation to slope-intercept form, solve for y 6x −y = 5 Subtract 6x from both sides −y = − 6x + 5 Divide both sides by −1 This will reverse the signs y = 6x − 5 m = 6 4y −9x = 8 is also in standard form
How do you find local maximum value of f using the first and . . . - Socratic Second Derivative Test This method, of course, will use the second derivative, so we should go ahead and differentiate the first derivative: f'' (x)=6x-12 The second derivative uses the concavity at a critical value to determine what type of extremum exists there The two concavities are displayed above
How do solve the following linear system?: x+2y=5 , -6x+3y . . . - Socratic One of the ways you can solve this linear system is by using substitution to find that the point of intersection is (13 5, 6 5), (2 6, 1 2) You can also use other methods, such as "making zeros" or graphing I apologize in advance for the length of this explanation, but it's good to know multiple ways of doing something (: Substitution: When we use the substitution method to solve linear
Determine the zeros of p (x)=x^3−5x^2−6x ? | Socratic Polinomial Degree= 3 Thus it will have 3 roots or zeroes p(x) = x3 − 5x2 −6x = x(x2 −5x −6) (common factor x) In this product we can say that x = 0 because if x = 0, then p(x) = 0 Now we have 2 ways to resolve the problem Method 1: The other factor x2 −5x −6 we can find the zeroes appliying general formula x = 5 ± √25 +24 2 = 5 ± 7 2 this gives two solutions (roots of equation
How do you graph -6x+9y=-18? | Socratic −6x + 9y = −18 This is a linear equation, because the equation does not have any exponents Graph it by putting the equation into either slope-intercept form y = mx + b or point- slope form y −y1 = m(x − x1) Isolate y by first adding 6x to each side: 9y = 6x −18 Divide each side by 9: y = 2 3x − 2 Now graph the line y = 2 3 x − 2 by first plotting the y intercept at (0, − 2
How do you simplify 2 ( x - 4) + 3 ( x - 2) = (6x) ( x ^ { 2} - 6x . . . If you factor the bottom of the right side of the equation, x2 −6x +8, you will also get the answer (x − 4)(x −2) Now, multiply the numerator of each fraction by the part of the LCD not already in the denominator, like so: