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What does $QAQ^{-1}$ actually mean? - Mathematics Stack Exchange Let me provide some context I was specifically looking at the application of linear algebra to the stress tensor $\sigma$ and how we get the transformed stress state in some rotated coordinate system by the following multiplication: $\sigma'=Q\sigma Q^{-1}(Q$ is a rotation matrix defined by the angle we want to rotate the axes)
factorial - Why does 0! = 1? - Mathematics Stack Exchange $\begingroup$ The theorem that $\binom{n}{k} = \frac{n!}{k!(n-k)!}$ already assumes $0!$ is defined to be $1$ Otherwise this would be restricted to $0 <k < n$ A reason that we do define $0!$ to be $1$ is so that we can cover those edge cases with the same formula, instead of having to treat them separately
1 8, 1 4, 1 2, 3 4,7 8英寸分别是多少厘米? - 知乎 把1英寸分成8等分: 1 8 1 4 3 8 1 2 5 8 3 4 7 8 英寸。 This is an arithmetic sequence since there is a common difference between each term In this case, adding 18 to the previous term in the sequence gives the next term In other words, an=a1+d(n−1) Arithmetic Sequence: d=1 8