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How does ABC + ABC + ABC simplify to (A + B)C? Simplified: (A + B)C' I completely understand how they got the non-simplified result from the table The simplification part is what is confusing me I've looked up some of the laws and theorems, and I'm sure they explain this, but I'm rusty and am having a hard time correlating the steps in-between to these individual laws theorems
Simplification of: AB + AC + BC in boolean algebra I am trying to understand the simplification of the boolean expression: AB + A'C + BC I know it simplifies to A'C + BC And I understand why, but I cannot figure out how to perform the simplific
Factoring $ (a+b) (a+c) (b+c)= (a+b+c) (ab+bc+ca)-abc$ An interesting question! In mathematics it is, IMO, very interesting how to speed up tedious verifications of identities The downvote may come from someone who does not consider this a valuable question, but I do, honestly
Boolean Simplification of ABC+ABC+ABC My question is how do I reduce $\bar A\bar B\bar C+A\bar B\bar C+AB\bar C$ To get $ (A+\bar B)\bar C$ I'm so lost just been trying to get it for awhile only using the 10 boolean simplification rules