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’ showing on page instead of - Stack Overflow So what's the problem, It's a ’ (RIGHT SINGLE QUOTATION MARK - U+2019) character which is being decoded as CP-1252 instead of UTF-8 If you check the Encodings table of this character at FileFormat Info, then you see that this character is in UTF-8 composed of bytes 0xE2, 0x80 and 0x99 And if you check the CP-1252 code page layout at Wikipedia, then you'll see that the hex bytes E2, 80 and
How to fix a No process is on the other end of the pipe error in SQL . . . The server was set to Windows Authentication only by default There isn't any notification, that the origin of the errors is that, so it's hard to figure it out The SQL Management studio does not warn you, even if you create a user with SQL Authentication only So the answer is: Switch from Windows to SQL Authentication: Right click on the server name and select properties; Select security
git: how to rename a branch (both local and remote)? I have a local branch master that points to a remote branch origin regacy (oops, typo!) How do I rename the remote branch to origin legacy or origin master? I tried: git remote rename regacy legac
How to fix SQL Server 2019 connection error due to certificate issue To improve the answer, let me sum up the comments: While setting TrustServerCertificate=True or Encrypt=false in the connection string is a quick fix, the recommended way of solving this issue is to provide a proper certificate for your SQL Server from a trusted CA To install a certificate for a single SQL Server instance (source): In SQL Server Configuration Manager, in the console pane
Looping through the content of a file in Bash - Stack Overflow Oh, I see many things have happened here: all the comments were deleted and the question being reopened Just for reference, the accepted answer in Read a file line by line assigning the value to a variable addresses the problem in a canonical way and should be preferred over the accepted one here
Finding and deleting duplicate values in a SQL table It's easy to find duplicates with one field: SELECT email, COUNT(email) FROM users GROUP BY email HAVING COUNT(email) gt; 1 So if we have a table ID NAME EMAIL 1 John asd@asd com 2 S