companydirectorylist.com  Global Business Directories and Company Directories
Search Business,Company,Industry :


Country Lists
USA Company Directories
Canada Business Lists
Australia Business Directories
France Company Lists
Italy Company Lists
Spain Company Directories
Switzerland Business Lists
Austria Company Directories
Belgium Business Directories
Hong Kong Company Lists
China Business Lists
Taiwan Company Lists
United Arab Emirates Company Directories


Industry Catalogs
USA Industry Directories












Company Directories & Business Directories

ABBA COMMUNICATIONS

OSHAWA-Canada

Company Name:
Corporate Name:
ABBA COMMUNICATIONS
Company Title:  
Company Description:  
Keywords to Search:  
Company Address: 843 King St W,OSHAWA,ON,Canada 
ZIP Code:
Postal Code:
L1J 
Telephone Number: 9055761212 
Fax Number: 9054040852 
Website:
 
Email:
 
USA SIC Code(Standard Industrial Classification Code):
49400 
USA SIC Description:
CELLULAR & MOBILE TELEPHONE EQUIP & SUPLS 
Number of Employees:
1 to 4 
Sales Amount:
$1 to 2.5 million 
Credit History:
Credit Report:
Good 
Contact Person:
 
Remove my name



copy and paste this google map to your website or blog!

Press copy button and paste into your blog or website.
(Please switch to 'HTML' mode when posting into your blog. Examples:
WordPress Example, Blogger Example)









Input Form:Deal with this potential dealer,buyer,seller,supplier,manufacturer,exporter,importer

(Any information to deal,buy, sell, quote for products or service)

Your Subject:
Your Comment or Review:
Security Code:



Previous company profile:
ABBOTT ROOFING
ABBOTT DRAFTING & DESIGN DIV OF R
ABBOTT DRAFTING & DESIGN
Next company profile:
ABS MOTORCYCLE SHOP LTD
ABS MOTORCYCLE SHOP LTD
AAMCO TRANSMISSIONS










Company News:
  • How to prove $\\operatorname{Tr}(AB) = \\operatorname{Tr}(BA)$?
    there is a similar thread here Coordinate-free proof of $\operatorname {Tr} (AB)=\operatorname {Tr} (BA)$?, but I'm only looking for a simple linear algebra proof
  • How many $4$-digit palindromes are divisible by $3$?
    How many 4 4 -digit palindromes are divisible by 3 3? I'm trying to figure this one out I know that if a number is divisible by 3 3, then the sum of its digits is divisible by 3 3 All I have done is listed out lots of numbers that work I haven't developed a nice technique for this yet
  • matrices - When will $AB=BA$? - Mathematics Stack Exchange
    Given two square matrices A, B A, B with same dimension, what conditions will lead to this result? Or what result will this condition lead to? I thought this is a quite simple question, but I can find little information about it Thanks
  • linear algebra - Does $\det (A + B) = \det (A) + \det (B)$ hold . . .
    But you are expected to think a bit about things before asking questions Sure, part of the question would still make sense to ask, but you would probably have known that the equality does not hold in general, and people might be focusing more on the more tricky part of the question
  • Proofs of determinants of block matrices [duplicate]
    I know that there are three important results when taking the Determinants of Block matrices $$\\begin{align}\\det \\begin{bmatrix} A amp; B \\\\ 0 amp; D \\end
  • The commutator of two matrices - Mathematics Stack Exchange
    The commutator [X, Y] of two matrices is defined by the equation $$\begin {align} [X, Y] = XY − YX \end {align}$$ Two anti-commuting matrices A and B satisfy $$\begin {align} A^2=I \qu
  • Show that $ e^{A+B}=e^A e^B$ - e^ {A+B}=e^A e^B$ - Mathematics Stack . . .
    As a remark, it is actually legitimate to assume that A A and B B are simultaneously diagonalisable (surprise, surprise!), so the proposition is trivial But obviously, the reason why we can make such an assumption is way beyond the scope of undergraduate (or even graduate) linear algebra courses
  • If eigenvalues are positive, is the matrix positive definite?
    This question does a great job of illustrating the problem with thinking about these things in terms of coordinates The thing that is positive-definite is not a matrix M M but the quadratic form x ↦ xTMx x ↦ x T M x, which is a very different beast from the linear transformation x ↦ Mx x ↦ M x For one thing, the quadratic form does not depend on the antisymmetric part of M M, so
  • Trace of AB = Trace of BA - Mathematics Stack Exchange
    We can define trace if A =∑i ei, Aei A = ∑ i e i, A e i where ei e i 's are standard column vectors, and x, y =xty x, y = x t y for suitable column vectors x, y x, y With this set up, I want to prove trace of AB and BA are same, so it's enough to prove that




Business Directories,Company Directories
Business Directories,Company Directories copyright ©2005-2012 
disclaimer