copy and paste this google map to your website or blog!
Press copy button and paste into your blog or website.
(Please switch to 'HTML' mode when posting into your blog. Examples: WordPress Example, Blogger Example)
Input Form:Deal with this potential dealer,buyer,seller,supplier,manufacturer,exporter,importer
(Any information to deal,buy, sell, quote for products or service)
linear algebra - matrix exponential and Spectral abscissa - Mathematics . . . $\lim_{t \rightarrow \infty} \|e^{tA}\| = 0$ if and only if $\alpha(A) < 0 $, where $\alpha$ is the Spectral abscissa, defined as $\max{Re(\lambda_i)}$ I tried to approach this problem by proving that $\|e^{tA}\| \leq \|e^{t\alpha(A)}\|$ but didn't succeed The hints given is First show what happens when you exponentiate a triangular matrix
Abscissa of convergence for a Dirichlet series Since $|f(n)| = 1$, it follows that $\sigma_a = 1$ (where $\sigma_a$ is the abscissa of absolute convergence), and we may conclude from general theory of Dirichlet series that $\sigma_c \in [0,1]$ My feeling is that there should be a bit of cancellation, resulting in $\sigma_c$ being smaller than 1, though I haven't been able to quantify this
coordinate systems - Abscissa, Ordinate, and Applicate -- Origins . . . Abscissa is found in Latin in 1656 in Exercitationum Mathematicarum by Frans van Schooten See page 285 [Bill Stockich] According to Cajori (1906, page 185), “The term abscissa occurs for the first time in a Latin work of 1659, written by Stefano degli Angeli (1623-1697), a professor of mathematics in Rome ”
Abscissa of absolute convergence of a Dirichlet series I'd like some help to prove the following theorem : Let $\sum_{n \geq 1}\frac{f(n)}{n^s}$ and $\sum_{n \geq 1}\frac{g(n)}{n^s}$ be two Dirichlet series with respective abscissas of absolute