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Understanding arr[::-1] in numpy. Is this a special case? In fact it is just interpreting that it needs to go till the boundary as arr [::1] gives normal array Is this just coded as a special case or is there something more going on?
c - What does *arr [] mean? - Stack Overflow 7 what does *arr[] mean? As standalone expression *arr[] is not valid For variable definitions there are two meanings here, depending of the context in which such an expression appears: Variable definition with initialiser (as per the OP's snippet) c Copy
c++ - Why is arr and arr the same? - Stack Overflow The question is why arr and arr evaluates to the same number If arr is a literal (not stored anyware), then the compiler should complain and say that arr is not an lvalue
What is the meaning of arr [:] in assignment in numpy? Your question involves a mix of basic Python syntax, and numpy specific details In many ways it is the same for lists, but not exactly arr[:, 0] returns the 1st column of arr (a view), arr[:,0]=10 sets the values of that column to 10 arr[:] returns arr (alist[:] returns a copy of a list) arr[:]=arr2 performs an inplace replacement; changing the values of arr to the values of arr2 The
What is the difference between * arr and * arr [0] in C++, if arr is an . . . 1 Suppose I have an array of integers called arr I am trying to understand the distinction between * arr and * arr[0] I read that in C++, arr is essentially a pointer to the first element in the array and arr is a pointer to the whole array They both return the same address, I get this part
Array increment positioning with respect to indexer in C - array [i . . . 3 41 4 5 In this example i = 3, so arr[3] = 40 It then increases the value from 40 to 41 So arr[i]++ increments the value of this particular index and a[i++] first increments the index and then gives the value for this index
How *( arr + 1) - arr is working to give the array size As others have mentioned, *( arr + 1) triggers undefined behavior because arr + 1 is a pointer to one-past-the end of an array of type int [7] and that pointer is subsequently dereferenced
c - Difference between *arr [] and **arr - Stack Overflow Here arr is itself a pointer to the type char* Note: In case 1 array arr degrades to a pointer to become the type char** but it's not possible the other way around i e, pointer in case 2 cannot become an array