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Why is y=a a horizontal asymptote on the polar coordinates? An asymptote is an asymptote It doesn't depend on how you represent it You could write it equivalently as y=a or r sin θ=a Ok so I plotted the polar curve The difference between my curve and the one on maple is the behavior of the curve as t tends to 0
Describing behavior on each side of a vertical asymptote Find the vertical asymptotes of the graph of F (x) = (3 - x) (x^2 - 16) ok if i factor the denominator i find the vertical asymptotes to be x = 4, x = -4 The 2nd part of the problem asks: Describe the behavior of f (x) to the left and right of each vertical asymptote I'm not sure what i need to write for this
What is an asymptote and why doesnt parabola have one? An asymptote is a straight line associated with a curve such that as a point moves along an infinite branch of the curve the distance from the point to the line approaches zero and the slope of the curve at the point approaches the slope of the line The word's origin is Greek and means "not intersecting"
Horizontal asymptotes - approaches from above or below? I seem to be having a lot of difficulty finding whether for a horizontal asymptote, whether the curve approaches the asymptote from above or below For example, for the problem y = \\frac{6x + 1}{1 - 2x}, I know that: For the vertical asymptote, x = 1 2, and that \\lim_{x \\to
Asymptote of a curve in polar coordinates • Physics Forums Homework Statement The curve has polar equation for Use the fact that to show the line is an asymptote to The Attempt at a Solution **Attempt** I understood the concept behind how this asymptote is calculated, but I am not very fluent in mathematics to convert the above information into a comprehensive proof