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Why is y=a a horizontal asymptote on the polar coordinates? Since y=rsint, substituting r=y sint into rt=a we get y=asint t By taking the limit of both sides as t->0 we get y=a The thing I don't understand is, why is y=a a horizontal asymptote on the polar coordinates? Isn't y=a only an asymptote on the cartesian coordinates of the curve rt=a(when you convert it in terms of x and y)?
Asymptote of a curve in polar coordinates - Physics Forums I understood the concept behind how this asymptote is calculated, but I am not very fluent in mathematics to convert the above information into a comprehensive proof Moreover, there is another statement that states that I have to make use of the information ## \lim_{\theta \rightarrow 0}x=+\infty##
Oblique Asymptotes: What happens to the Remainder? - Physics Forums An "asymptote" is a line that a curve approaches as x goes to, in this case, negative infinity and infinity Yes, long division gives a quotient of -3x- 3 with a remaider of -1 Yes, long division gives a quotient of -3x- 3 with a remaider of -1
Determining the horizontal asymptote - Physics Forums My interest is on the horizontal asymptote, now considering the degree of polynomial and leading coefficients, i have ##y=\dfrac{2}{1} =2## Therefore ##y=2## is the horizontal asymptote The part that i do not seem to get is (i already checked this on desmos) why an asymptote can be regarded as such if it is crossing the curve
Vertical Asymptote: Is f Defined at x=1? - Physics Forums Homework Statement True False If the line x=1 is a vertical asymptote of y = f(x), then f is not defined at 1 Homework Equations none The Attempt at a Solution I originally believed this was true, but on finding it was false it sought a counter example: if for example f(x) = 1 x if x !=
Horizontal asymptotes - approaches from above or below? - Physics Forums I seem to be having a lot of difficulty finding whether for a horizontal asymptote, whether the curve approaches the asymptote from above or below For example, for the problem y = \\frac{6x + 1}{1 - 2x}, I know that: For the vertical asymptote, x = 1 2, and that \\lim_{x \\to
Describing behavior on each side of a vertical asymptote - Physics Forums Find the vertical asymptotes of the graph of F(x) = (3 - x) (x^2 - 16) ok if i factor the denominator i find the vertical asymptotes to be x = 4, x = -4 The 2nd part of the problem asks: Describe the behavior of f(x) to the left and right of each vertical asymptote I'm not sure
What is an asymptote and how do we find it in graphing ln(x)? Homework Statement the qns is : sketch the graph of y=3ln(x+2) , showing clearing the asymptote and the x-intercept im wondering wat is asymptote and how we find it :confused: Homework Equations The Attempt at a Solution