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O que é Backus-Naur Form (BNF)? - Stack Overflow em Português BNF (Backus-Naur Form), foi originalmente criada por John Backus e Peter Naur, é uma metassintaxe usada para expressar gramáticas livres de contexto Com ela, é possível especificar quais sequências de símbolos constituem um programa sintaticamente válido em um determinado idioma A relação influência nas linguagens de programação é que a BNF foi inicialmente desenvolvida para
BNF vs EBNF vs ABNF: which to choose? - Stack Overflow The EBNF is the extended newer version of BNF, so the problem becomes simpler: EBNF vs ABNF I'm not an expert, but think that it should depend on a language, whose syntax you want to define
BNF grammar associativity - Stack Overflow I'm trying to understand how left and right associative grammars work and I need a little help So I decided to come up an example and ask for some clarification Basically, I want to create a gram
notation - How can I write a sentence in BNF? - Stack Overflow A complete English grammar expressed in BNF would surely be exceedingly complex BNF is better suited to grammars of computer languages and formats You might have a BNF description of JSON, for example, or of allowable syntax in C or Java
syntax - Bracket and brace usage in BNF? - Stack Overflow Which dialect of BNF are you using? There are many, and they have different sets of rules Is a parenthesis a metacharacter or a literal character? Maybe you should use LPAREN and RPAREN as token names for left parenthesis and right parenthesis You casually mention EBNF one place; the rules for EBNF are very different from most other BNF-related systems (which is one reason why EBNF is not
bnf - Backus–Naur form with boolean algebra. Problem with brackets and . . . I assume that you want to define a grammar for boolean expressions using the Backus-Naur form, and that your examples are concrete instances of such expressions There are multiple problems with your grammar: First of all, you want your grammar to only generate correct boolean expressions With your grammar, you could generate a simple operator ∨ as valid expression using the path <variable