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How do I use %s in C correctly? - Stack Overflow For both *printf and *scanf, %s expects the corresponding argument to be of type char *, and for scanf, it had better point to a writable buffer (i e , not a string literal)
c - What does %. *s mean in printf? - Stack Overflow It's worth mentioning that the likely purpose of this code, especially when used with %s, is to print a sub-string of the original string In this use case, str would point to somewhere inside the original string (possibly at the beginning), and str_len will specify the length of the sub-string that should be printed
c++ - . c vs . cc vs. . cpp vs . hpp vs . h vs . cxx - Stack Overflow Historically, the first extensions used for C++ were c and h, exactly like for C This caused practical problems, especially the c which didn't allow build systems to easily differentiate C++ and C files Unix, on which C++ has been developed, has case sensitive file systems So some used C for C++ files
What does %s and %d mean in printf in the C language? %s tells printf that the corresponding argument is to be treated as a string (in C terms, a 0-terminated sequence of char); the type of the corresponding argument must be char * %d tells printf that the corresponding argument is to be treated as an integer value; the type of the corresponding argument must be int
What is the meaning of %-*. *s in a printf format string? But it's more like a law text than a tutorial, so it will be hard to understand I didn't know * * and had to read the man page myself It's interesting Let's start with a simple printf("%s", "abc") It will print the string abc printf("%8s", "abc") will print abc, including 5 leading spaces: 8 is the "field width" Think of a table of data
How to correctly printf strings and characters with %s and %c name = 0xbff5391b name[0] = 0xbff5391b name printed as %s is siva *name = s name[0] = s So 'name' is actually a pointer to the array of characters in memory If you try reading the first four bytes at 0xbff5391b, you will see 's', 'i', 'v' and 'a'
Difference between and in C? - Stack Overflow In your teacher's example a b, the left operand 4 and the right operand 8 are both non-zero So the condition will become true In your teacher's other example a b, the left operand 4 or 0100 and the right operand 8 or 01000 copies no bits to the result This is because there are no common set bits in either operand