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java - Why 010 equals 8? - Stack Overflow As everybody mentioned here that 010 is an Octal Integer literal The leading 0 specifies that it is an octal representation Actual value will be : 1*8^1 + 0*8^0 = 8(decimal) = 1000(binary-only last 4 digits) Now coming back to the SOP : System out println(010|4); Applying Bitwise OR on 010 and 4(considering only the last 4 digits) => 1000
Why `var = 010` gives `var` value `8` in C? - Stack Overflow 010 is an integer constant (i e literal), encoded in octal: 001 == 1 002 == 2 007 == 7 010 == 8 When you call printf with a format specifier %d, it prints the value of the given signed integer encoded in decimal, and therefore, you will see the character 8 written to the output
Why is initializing an integer in C++ to 010 different from . . . Because it's interpreting 010 as a number in octal format And in a base-8 system, the number 10 is equal to the number 8 in base-10 (our standard counting system) More generally, in the world of C++, prefixing an integer literal with 0 specifies an octal literal, so the compiler is behaving exactly as expected
What is . 010 in fractional inches? - TalkBass. com My math skills are escaping me and I don't have a set of feeler gauges I do have a ruler that measures down to 1 64" What is the closest 64th that I can use to measure 010"? It doesn't need to be perfect! Thanks